Factor Formulae - Derivation


$ \displaystyle \begin{array}{l}\sin (\alpha +\beta )=\sin \alpha \cos \beta +\cos \alpha \sin \beta ---(1)\\\\ \sin (\alpha -\beta )=\sin \alpha \cos \beta -\cos \alpha \sin \beta ---(2)\ \ \ \end{array}$

ဆိုတဲ့ Sum and Difference Formulae ေတြ α€€ို α€™ွတ္α€™ိαΎα€€α€™α€š္ ထင္ပါα€α€š္။

α€Šီα€™ွ်ျခင္း (1) α€”ဲα‚” (2) α€€ို ေပါင္းα€œိုα€€္α€™α€š္...။

$ \displaystyle \sin (\alpha +\beta )+\ \sin (\alpha -\beta )=2\sin \alpha \cos \beta ---(*)$

ဆိုၿပီး α€›α€œာα€™ွာေပါ့...။

$ \displaystyle \alpha +\beta =\theta $ α€”ဲα‚” $ \displaystyle \alpha -\beta =\phi $ α€œိုα‚” ထားα€œိုα€€္α€™α€š္။

α€’ါဆိုရင္ $ \displaystyle \alpha =\frac{{\theta +\phi }}{2}$ α€”ဲα‚” $ \displaystyle \beta =\frac{{\theta -\phi }}{2}$ ျα€–α€…္α€žြားα€™ွာေပါ့...။

$ \displaystyle \alpha +\beta =\theta ,\ \alpha -\beta =\phi ,\ \ \alpha =\frac{{\theta +\phi }}{2},\beta =\frac{{\theta -\phi }}{2}$ တိုα‚”α€€ို (*) α€™ွာ ထစားα€žြင္းα€œိုα€€္တဲ့ ထခါ α€™ွာေတာ့ ေထာα€€္ပါ factor formula α€€ို α€›α€›ွိα€™ွာ ျα€–α€…္ပါα€α€š္။

$ \displaystyle \sin \theta +\ \sin \phi =2\sin \frac{{\theta +\phi }}{2}\cos \frac{{\theta -\phi }}{2}$


α€’ီတစ္ခါ α€Šီα€™ွ်ျခင္း (1) ထဲα€€ (2) α€€ို ႏႈတ္ပါα€™α€š္...။

$ \displaystyle \sin (\alpha +\beta )-\ \sin (\alpha -\beta )=2\cos \alpha \sin \beta $

ထထက္ကထတိုင္း α€žα€€္ဆိုင္α€›ာတန္α€–ိုးေတြ ထစားα€žြင္းα€œိုα€€္ရင္ ...။

$ \displaystyle \sin \theta -\ \sin \phi =2\cos \frac{{\theta +\phi }}{2}\sin \frac{{\theta -\phi }}{2}$


Identity တစ္ခု ထပ္ရပါα€™α€š္...။

ေα€”ာα€€္ထပ္α€Šီα€™ွ်ျခင္း ႏွα€…္ၾကာင္း α€€ို ဆက္αΎα€€α€Š့္α€›ေထာင္...။

$ \displaystyle \begin{array}{l} \cos (\alpha +\beta )=\cos \alpha \cos \beta -\sin \alpha \sin \beta ---(3)\\\\ \cos (\alpha -\beta )=\cos \alpha \cos \beta +\sin \alpha \sin \beta ---(4)\ \ \ \end{array}$

ထထက္ပါထတိုင္း α€Šီα€™ ွ်ျခင္း ႏွα€…္ေၾကာင္း (3) α€”ဲα‚” (4) α€€ို ေပါင္းတစ္α€œွα€Š့္ ႏႈတ္တစ္α€œွα€Š့္ α€œုပ္α€œိုα€€္ရင္ ...။

$ \displaystyle \begin{array}{l}(3)+(4)\Rightarrow \ \ \ \cos (\alpha +\beta )+\ \cos (\alpha -\beta )=2\cos \alpha \cos \beta \\\\(3)-(4)\Rightarrow \ \ \ \cos (\alpha +\beta )-\ \cos (\alpha -\beta )=-2\cos \alpha \cos \beta \end{array}$

ထထက္α€™ွာ α€›ွာခဲ့ၿပီး ျα€–α€…္တဲ့ $ \displaystyle \alpha +\beta =\theta ,\ \alpha -\beta =\phi ,\ \ \alpha =\frac{{\theta +\phi }}{2},\beta =\frac{{\theta -\phi }}{2}$ တိုα‚”α€€ို α€žα€€္ဆိုင္α€›ာ တန္α€–ိုးေတြα€™ွာ ထစားα€žြင္းα€œိုα€€္ရင္...။

$ \displaystyle \begin{array}{l}\cos \theta +\ \cos \phi =2\cos \displaystyle \frac{{\theta +\phi }}{2}\cos \displaystyle \frac{{\theta -\phi }}{2}\\\\\cos \theta -\ \cos \phi =-2\sin \displaystyle \frac{{\theta +\phi }}{2}\sin \displaystyle \frac{{\theta -\phi }}{2}\end{array}$


α€…ာဖတ်α€žူ၏ ထမြင်α€€ို α€œေးα€…ားα€…ွာα€…ောင့်α€™ျှော်α€œျα€€်!

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