Random Experiment
A random experiment (for brevity, we will simply call them experiment instead) is an experiment or a process for which the exact result of this experiment cannot be predicted.αα်αα့်ααα် ααα်αို αိαျα ွာ αြိုαα်αα့်αှα်းαိုα်αြα်း ααှိαော α α်းαα်αျα်αို αျαα်း α α်းαα်αျα် (random experiment) αုαေါ်αα်။
•The tossing of a coin - αုံαှα်αြα ်αော (αα်ααိုα်αော) α‘αြွေα ေ့αို αα ်αြှောα်αြα်း
• rolling a die αုံαှα်αြα ်αော (αα်ααိုα်αော) α‘ံα ာαုံးαေါα်αြα်း
Outcome
A single specific result of an experiment is called an outcome.α α်းαα်αျα်αα ်αု၏ ααα် αα ်αုαျα်းα ီαို Outcom αုαေါ်αα်။
α αျα်αှာαှိαော α‘ံα ာαုံးαα ်αုαို αှိα့်αိုα်αα်αိုαါα ို့။ 1 αှာ 6 α‘αိ αα်αα့်ααα်းααို αျαိုα်αα်။ α‘αိုαါ 1 αှာ 6 α‘αိ αျαောα်αိုα်αော ααα်းαα ်αုαျα်းα ီαို outcome αုαေါ်αα်
Sample Space
The set of all possible outcomes of an experiment is called the sample space.α α်းαα်αှုαα ်αု၏ αြα ်αိုα်αော ααα်αျားα‘ားαုံးαါαα်αော α‘α ုαို sample space αေါ်αα်။ Sample Space αို S αြα့် αα်αှα်αα်။
α₯ααာ α‘ံα ာαုံးαေါα်αော α α်းαα်αျα်၏ sample space αှာ $ \displaystyle S=\left\{ {1,2,3,4,5,6} \right\}$ αြα ်αα်။
Event
An event is a subset of a sample space. Sample Space αဲαှိ αိုαျα်αော outcomes αျားαါαော α‘α ိα်α‘αိုα်း (sample space ၏ α‘α ုαိုα်း) αို event αုαေါ်αα်။α₯ααာ α‘ံα ာαုံးαေါα်αြα်းαွα် sample space αှာ $ \displaystyle S=\left\{ {1,2,3,4,5,6} \right\}$ αြα ်αα်။ α‘ံα ာαုံးαေါα်αူα α ုံαိα်းαျားαာ αျαိုαα်αိုαါα ို့။ αိုα‘αါ event αှာ $ \displaystyle E=\left\{ {2,4,6} \right\}$ αြα ်αα်။
Probability
Let $S$ be a finite sample space for an experiment such that all outcomes are equally likely which means that they are random and have an equal likelihood of occurrence. Then the probability of an event $E$, denoted by $π (E)$, in the sample space $S$, is defined byIn symbols,
where $n(E)$ denotes the number of elements in the event $E$ and $n(S)$ denotes the number of outcomes in the sample space $S$.
αိုαျα်αော αြα ်αα် αွα်αါαα်αော α‘α ုαα်α‘αေα‘αွα် (events ၏ α‘α ုαα်α‘αေα‘αွα်) αှα့် αြα ်αိုα်αော α‘α ုαα်α‘αေα‘αွα်α ုα ုαေါα်း (sample space ၏ α‘α ုαα်α‘αေα‘αွα်) αို့၏ α‘αျိုးαို event αα ်αု၏ probability (αြα ်αα်α ွα်း) αုαေါ်αα်။
Note
- For any event $E$, $P(E)$ is a real number such that $0 \le P(E) \le 1$.
- $P(\varnothing )=0$ and $P(S)=1$ (This means that the probability of an impossible event is 0 and that of a sure event is 1 .)
- For any event $E$, $P(E) + P(\text{not}\ E) = 1$.
Independent Events
Two events are independent if the occurrence of any one of them does not affect the probability of the other.αြα ်αα်αα ်αု (event) αြα ်αြα်း၊ ααြα ်αြα်းαα် α‘αြားαြα ်αα်αα ်αု αြα ်αြα်း၊ ααြα ်αြα်းαှα့် αα်αα်αှု၊ αα်αိုα်αှုααှိαျှα် ၎α်းαြα ်αα်αှα ်αု αို independent events αုαေါ်αα်။ independent events αျားαα် ααြိုα်αα်αြα ်αိုα်αα်။
$E_1$ αှα့် $E_2$ αα် independent events αျားαြα ်αြαျှα် α‘αိုαါ event αှα ်αု ααြိုα်αα်αြα ်αα် probability αှာ
αြα ်αα်။
α₯ααာ α‘ံα ာαုံးαှα ်αုံးαို ααြိုα်αα်αေါα်αα် αိုαါα ို့။ αααα‘ံα ာαုံး 6 αျαြα်းααျαြα်းαα် αုαိαα‘ံα ာαုံး 6 αျαြα်းααျαြα်းαှα့် αα်αိုα်αှုααှိαေ။ αိုαြောα့် α‘ံα ာαုံးαှα ်αုαုံးαွα် 6 αျ αိုα်αα်။ α‘ံα ာαုံးαှα ်αုαုံးαွα် 6 αျαα် probability αို α‘ောα်αါα‘αိုα်း αွα်αူαိုα်αα်။
$ \begin{array}{l} E_1= \text{6 appears on first die}\\ E_2= \text{6 appears on first die}\\ \therefore P(E_1)=P(E_2)=\displaystyle \frac{1}{6}\\ P(E_1\ \text{and}\ E_2)= P(E_1)\times P(E_2)\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\displaystyle \frac{1}{6}\times \displaystyle \frac{1}{6}=\displaystyle \frac{1}{36} \\ \end{array}$
Dependent Events
Two events are dependent when the outcome of the first event influences the outcome of the second event.αြα ်αα်αα ်αု (event) αြα ်αြα်း၊ ααြα ်αြα်းαα် α‘αြားαြα ်αα်αα ်αု αြα ်αြα်း၊ ααြα ်αြα်းαှα့် αα်αα်αှု၊ αα်αိုα်αှုαှိαြီး ၎α်းαြα ်αα်αှα ်αု ααြိုα်αှα် (αို့ααုα်) αα်αိုα် αြα ်αိုα်αျှα် ၎α်းαို့αို dependent events αုαေါ်αα်။ dependent events αျားαα်αα်း ααြိုα်αှα်αြα ်αိုα်αα်။
$E_1$ αှα့် $E_2$ αα် dependent events αျားαြα ်αြαျှα် α‘αိုαါ event αှα ်αု ααြိုα်αα်αြα ်αα် probability αှာ
αြα ်αα်။
α₯ααာ αုံးαα ်αုံးαဲαွα် α‘αီαောα်αေါ်αီ 5 αုံးαှα့် α‘αα်αောα်αေါ်αီ 5 αုံး αှိαα်αိုαါα ို့။ αိုαုံးαဲαှ αေါ်αီαှα ်αုံးαို ααြိုα်αα် αူαိုα်αျှα် ααှိαာαော αေါ်αီαှα ်αုံး αှα ်αုαုံး α‘αီαောα် αြα ်αိုα်αα်။ αို့αာαွα် αုαိααေါ်αီαုံး α‘αီαောα်αြα ်αα် probability αα် ααααေါ်αီαုံး α‘αီαောα်αြα ်αော probability α‘αေါ်αွα် αα်αα်αှုαှိαေαα်။ αေါ်αီαှα ်αုαုံး α‘αီαောα်αြα ်αα် probability αို α‘ောα်αါα‘αိုα်း αွα်αူαိုα်αα်။
$ \begin{array}{l} \text{For choosing first marble},\\ S=\left\{\text{5 red marbles and 5 black marbles}\right\}\\ n(S)=10\\ E_1= \left\{\text{red marbles in a box}\right\}\\ n(E_1)=5\\ P(E_1)=\displaystyle \frac{5}{10}=\frac{1}{2}\\ \text{For choosing second marble},\\ S=\left\{\text{4 red marbles and 5 black marbles}\right\}\\ n(S)=9\\ E_2= \left\{\text{red marbles in a box after choosing first marble}\right\}\\ n(E_2)=4\\ P(E_2)=\displaystyle \frac{4}{9}\\ \therefore P(E_1\ \text{and}\ E_2)= P(E_1)\times P(E_2)\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\displaystyle \frac{1}{2}\times \displaystyle \frac{4}{9}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\displaystyle \frac{2}{9} \\ \end{array}$
αှα်αျα်။ ။α‘αα်၍ ααααေါ်αီαူ α‘αောα်αှα်αားαြီး αြα်αα့်၊ αိုαောα်αှ αုαိααေါ်αီαို αူαျှα် $E_1$ αှα့် $E_2$ αှာ independent events αျား αြα ်αွားαα်။
Mutually Exclusive Events
Two events $E_1$ and $E_2$ are mutually exclusive if they cannot occur jointly, that is, they do not have common outcomes.αြα ်αα်αα ်αု αြα ်αα့်α‘αါ α‘αြားαြα ်αα်αα ်αု αုံးαααြα ်αိုα်αော့αျှα် α‘αိုαါαြα ်αα်αှα ်αုαို mutually exclusive events αုαေါ်αα်။ $E_1$ αှα့် $E_2$ αα် mutually exclusive events αျားαြα ်αြαျှα် $E_1$ αို့ααုα် $E_2$ αα ်αုαာ αြα ်αိုα်αα်။
$E_1$ αှα့် $E_2$ αα် mutually exclusive events αျားαြα ်αြαျှα် α‘αိုαါ event αှα ်αု αα ်αုααုα် αα ်αုαြα ်αα် probability αှာ
αြα ်αα်။
α₯ααာ α‘ံα ာαုံးαα ်αု αေါα်αα် αိုαါα ို့။ sample space αှာ $S=\left\{1,2,3,4,5,6\right\}$ αြα ်αြီး outcomes αα ်αုαျα်းα ီαα် mutually exclusive αြα ်αြαα်။ α‘αα်၍ α‘ံα ာαေါα်αူαα် 1 αို့ααုα် 6 αျαα်α‘αိုαှိαျှα် α‘αိုαါ αြα ်αα်α‘αွα် probability αို α‘ောα်αါα‘αိုα်း αွα်αူαိုα်αα်။
$ \begin{array}{l} S=\left\{1,2,3,4,5,6\right\}\\ E_1= \left\{1\right\}\\ E_2= \left\{6\right\}\\ \therefore P(E_1)=P(E_2)=\displaystyle \frac{1}{6}\\ P(E_1\ \text{or}\ E_2)= P(E_1) + P(E_2)\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\displaystyle \frac{1}{6}+\displaystyle \frac{1}{6}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\displaystyle \frac{2}{6}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\displaystyle \frac{1}{3} \\ \end{array}$
Mutually Inclusive Events
Two events $E_1$ and $E_2$ are mutually inclusive if they can happen at the same time.$E_1$ αှα့် $E_2$ αα် mutually inclusive events αျားαြα ်αြαျှα် α‘αိုαါαြα ်αα်αှα ်αုαα် αα ်αုααုα် αα ်αုαြα ်αိုα်ααို ααြိုα်αα်αα်း αြα ်αိုα်αα်။
$E_1$ αှα့် $E_2$ αα် mutually inclusive events αျားαြα ်αြαျှα် α‘αိုαါ event αှα ်αု αα ်αုααုα် αα ်αုαြα ်αα် probability αှာ
αြα ်αα်။
α₯ααာ α‘ံα ာαုံးαα ်αု αေါα်αα် αိုαါα ို့။ sample space αှာ $S=\left\{1,2,3,4,5,6\right\}$ αြα ်αα်။ α‘ံα ာαေါα်αူαα် α ုံαိα်း αို့ααုα် 6 ၏ααွဲαိα်းαျား αျαα်α‘αိုαှိαα်αုαူααα်။ α ုံαိα်းα‘αွα် event $(E_1)$αှာ $\left\{2,4,6\right\}$ αြα ်αြီး 6 ၏ααွဲαိα်းα‘αွα် event $(E_2)$ αှာ $\left\{1,2,3,6\right\}$ αြα ်αα်။ αြα ်αα်αှα ်αုαွα် αα်αေαော outcomes αါαောαြောα့် $E_1$ αို့ααုα် $E_2$ αြα ်αα် probability αို α‘ောα်αါα‘αိုα်း αွα်αူαိုα်αα်။
$ \begin{array}{l} S=\left\{1,2,3,4,5,6\right\}\\ E_1= \left\{\text{even numbers}\right\}=\left\{2,4,6\right\}\\ E_2= \left\{\text{factors of 6}\right\}=\left\{1,2,3,6\right\}\\ \therefore P(E_1)=\displaystyle \frac{3}{6}\\ \ \ \ \ P(E_2)=\displaystyle \frac{4}{6}\\ \ \ \ \ P(E_1\ \text{and}\ E_2)=P(E_1) \times P(E_2)\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \displaystyle \frac{3}{6}\times \displaystyle\frac{4}{6}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \displaystyle\frac{1}{3} \\ \ \ \ \ P(E_1\ \text{or}\ E_2)= P(E_1) + P(E_2) - P(E_1\ \text{and}\ E_2)\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\displaystyle \frac{3}{6}+\displaystyle \frac{4}{6}-\displaystyle \frac{1}{3}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\displaystyle \frac{5}{6} \end{array}$
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